Question
Evaluate the integral.$ \displaystyle \int_1^2 \frac{(\ln x)^2}{x^3} dx $
Step 1
We let $u = (\ln x)^2$ and $dv = \frac{1}{x^3} dx$. Then we find $du = 2\ln x \cdot \frac{1}{x} dx$ and $v = -\frac{1}{2x^2}$. Show more…
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