Question
Evaluate the integral.$ \displaystyle \int_1^4 \frac{e^{\sqrt{t}}}{\sqrt{t}}\ dt $
Step 1
We take $u = \sqrt{t}$. Then $du = \frac{1}{2\sqrt{t}} dt$ or equivalently, $2 du = \frac{dt}{\sqrt{t}}$. This is precisely what we see in the original problem. Show more…
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