Question
Evaluate the integral.$$\int \sin 5 \theta \sin \theta d \theta$$
Step 1
In this case, $a = 5\theta$ and $b = \theta$. So, we can rewrite the integral as follows: $$\int \sin 5 \theta \sin \theta d \theta = \frac{1}{2} \int [\cos(5\theta - \theta) - \cos(5\theta + \theta)] d \theta$$ Show more…
Show all steps
Your feedback will help us improve your experience
Prakash Hampole and 50 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the integral. $$\int \sin ^{2} 5 \theta d \theta$$
PRINCIPLES OF INTEGRAL EVALUATION
Integrating Trigonometric Functions
Evaluate the integral. $$\int \cos \theta \cos ^{5}(\sin \theta) d \theta$$
Techniques of Integration
Trigonometric Integrals
Determine $\int \sin ^{5} \theta \mathrm{d} \theta$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD