Question
Evaluate the integral. $\int_0^1 \frac{r^3}{\sqrt{4+r^2}} d r$
Step 1
Notice that the expression under the square root is \(4 + r^2\). A common technique is to use the substitution \(u = 4 + r^2\). This implies that \(du = 2r \, dr\), or equivalently, \(r \, dr = \frac{1}{2} \, du\). Show more…
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Evaluate the integral. $ \displaystyle \int_0^1 \frac{r^3}{\sqrt{4 + r^2}} dr $
Techniques of Integration
Integration by Parts
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