00:01
In this question, we're going to evaluate the integral using integration by parts with the indicated choices of u and dv.
00:07
Here, i'm finding the antiderivative of x e to the 2x power, letting u equal x and my dv equal e to the 2x dx.
00:18
So first of all, let's remember our integration by parts formula.
00:25
I know that the integral of u dv, that's equal to u times v minus the integral of v du.
00:39
Now my u is equal to x and my dv is equal to e to the 2x dx.
00:51
So first of all, what is my du? well, if u equals x, my du equals dx.
01:02
Well, how about my v? if dv is e to the 2x dx, my v is the antiderivative of dv.
01:12
What is that? it's e to the power of 2x being divided by 2...