00:01
Hello, today we'll be doing problem 9 .18, and this problem asks us to explain how, when you react, this reactant with water, how do we get these two products? and why are they substitution products and how do we essentially get these? so let's go through the mechanism to figure out how we get these two substitution products.
00:26
So if we see here we have hydrocarbon with a good leaving group being chlorine.
00:34
So obviously a few things can happen.
00:38
Firstly because this is a good leaving group is electronegative, right away this chlorine molecule can spontaneously fall off.
00:47
And if that were the case, then we would get an intermediate being this secondary carbocadion right here, plus our cl minus, which falls off.
01:05
At this point, then we need to neutralize our carbocatin intermediate.
01:09
It is very electrophilic, and we have actually a good nucleophile being water.
01:15
But also, some can argue that chlorine is also a good nucleophile, but because it is formally negatively charged, but for every one molecule of this that reacts to have chlorine fall off, we have thousands of water molecules in the reaction vessel because water in this case is our solvent.
01:35
So for every one of these chlorine ions, we have thousands or if not millions of these water molecules present in our reaction mixture, making this the more probable nucleophile.
01:48
So because of that, we know that our nucleophile will attack the carbocadion center, forming a form.
01:57
Bond and neutralizing this carbocatao.
02:03
This gives us this product here with a formal positive charge on oxygen.
02:20
However, oxygen does not like positive charge as likes being neutral or negative.
02:24
And also we have a negatively charged chlorine ion still here.
02:29
So a negative plus a positive is neutral...