00:01
Hello, hope you're doing well.
00:03
So we have our function f of x here and our k value here.
00:06
So saying this is our f of x and this is our k is essentially the same as the division problem, 2x cubed plus x squared plus x minus 8 over x minus k and k is equal to minus 1.
00:21
So it will be x plus 1.
00:23
So we'll keep this in mind for later.
00:25
So using synthetic division, we're going to write out all of the coefficients of our f of x here.
00:31
We have coefficient of two.
00:34
These are both one, so one and one, and then minus eight.
00:40
And then we have k is equal to minus one to go on the outside.
00:44
So we can use a synthetic division to divide these.
00:46
So bringing the two down, we have two times minus one, gives us minus two, one minus two gives us minus one.
00:52
Minus one times minus one gives us one.
00:54
One plus one is two.
00:56
Two times minus one is minus two, and minus eight minus two is minus ten.
01:01
So this is our remainder term here.
01:05
This is our x to the zero, our constant term.
01:08
This is our x to the one term, and this is our x squared two...