Express the ep $\rightarrow$ eX differential cross section (8.34) in terms of $\sigma_{T, L} .$ That is, show that
$$
\left.\frac{d \sigma}{d E^{\prime} d \Omega}\right|_{\mathrm{lab}}=\Gamma\left(\sigma_{T}+\varepsilon \sigma_{L}\right)
$$
where
$$
\begin{aligned}
&\Gamma=\frac{\alpha K}{2 \pi^{2}\left|q^{2}\right|} \frac{E^{\prime}}{E} \frac{1}{1-\varepsilon} \\
&\varepsilon=\left(1-2 \frac{\nu^{2}-q^{2}}{q^{2}} \tan ^{2} \frac{\theta}{2}\right)^{-1}
\end{aligned}
$$