00:02
All right, so for this problem, we're going to express the following logarithms in terms of ln of 5 and ln's of x.
00:14
Okay.
00:16
Okay, we'll begin with ln of 1 over 125.
00:25
Okay.
00:26
This can be written as differences of difference of two logarithms.
00:32
We have ln of 1, minus.
00:34
Minus ln of 125.
00:37
Okay, and we know that ln of 1 is just equal to 0.
00:43
Alright, so we have negative ln of 125.
00:48
Okay, and 125 can be written as 5 raised to negative, raise to 3 or 5 q.
00:59
Okay, and applying the property of logarithm, we have negative 3 ln of 5.
01:06
Okay, so this is our answer for letter 8.
01:10
Next up we have ln of 9 .8.
01:15
Okay, so ln of 9 .8.
01:20
Okay, so we'll rewrite 9 .8 as a fraction.
01:26
So 9 .8 is actually equivalent to 49 over 5.
01:33
Okay, so we have ln of 49 over 5.
01:36
And just what we did from the previous item okay we have ln of 49 minus ln of 5 okay and we know that ln of 49 can be written as ln of 7 quantity square because 7 square is 49 minus ln of 5 okay and applying the property of logarithms okay we have 2 ln of 7 minus l n of 5.
02:11
Okay, so this is our answer for letter.
02:15
Okay, next up we have letter c.
02:20
Okay, so for letter c, we have ln of 7, square root of 7.
02:30
Okay, so let's rewrite square root of 7 as a term with a fractional exponent.
02:40
So this is ln of 7 times, okay, times 7 raise 2 1 half.
02:48
Okay, applying the rules of exponent, we have ln of 7 raised to 1 times 7 raised 1 half to 7 raised to 3 halves.
02:58
Okay.
02:59
And then applying the rule of logarithm, we have 3 over 2, ln of 7.
03:05
Okay, so this is our answer for letter c.
03:09
Okay, then we have letter d, okay, this ln of 1 -225.
03:18
Okay, okay, so by prime factorization, ln225 is actually equal to 5 squared, okay, times 7 squared.
03:39
Okay, and applying the rule of exponent, we have, we can rewrite this one as sum of two logarithms, we have ln of 5 squared plus ln of 7 square.
03:53
So i have to correct myself...