00:01
Over this problem, we're given a graph that shows the voltage in a capacitor over time when it's connected to a battery.
00:07
We're also given the resistance, which is r is equal to 4 ,700 oms.
00:19
For part a, we're asked to find a voltage in this battery.
00:24
Well, once the capacitor reaches maximum charge, it'll be the same voltage as the battery.
00:29
And so it levels off at 9 volts.
00:34
Part b wants to find the time constant tally which is equal to r times c.
00:41
And we use the equation for the voltage in the capacitor when it's charging.
00:47
So vc is equal to voltage in the battery times 1 minus e to the minus t over rc.
00:58
Now from the graph, if we say add t equals to one second, then we get the voltage in the capacitor to be 4 volts.
01:13
Now with this information, all we need to do is now solve for r times c...