00:01
Hi, in the given problem, there are two segments in arc shape, segments of the current carrying wire.
00:11
The first one is in the form of a semicircle like this.
00:23
This is the center of the semicircle and this center is shared by one more arc here.
00:35
This arc is making an angle.
00:38
This is a smaller arc and it is making an angle of 120 degree.
00:46
At the center which is shared by both of these loops.
00:51
The center is p.
00:53
The current here passing through the lower arc, semi -circular arc, this is i -1 and passing through the upper arc, this is i -2.
01:01
Here is this angle theta which whose value is 120 degree current i1 is having a magnitude 0 .40 amper radius of the bigger loop that is 5 .0 cm current in the smaller loop upper loop that is i2 is equal to twice of i1 which will become 0 .80amper.
01:29
Here and its radius here is that is a smaller loop having a radius equal to 4 .0 centimeter now in the first part of the problem we have to find net magnetic field at the common center along with its direction so first of all b1 means magnetic field due to the semicircular arc at the center it will be given by mu not i1 divided by 4 r1.
02:01
So plugging in known values here, 4 pi into 10 dash per minus 7, tesla meter per ampere for mu not into i1, which is 0 .40 ampere divided by 4 times of r, r1, which is 5 cm or 5 into 10 dash per minus 2 meter.
02:20
So this magnetic field here will come out to be 0 .25 into 10 dash per minus 5, tesla, or or we can say this is 2 .5 micro tesla and its direction will be as the current is in clockwise direction sorry counterclockwise direction so this face will start behaving like a north pole and the magnetic field comes out of the north pole so this magnetic field will be outward similarly, the magnetic field due to the smaller loop and that will be given by theta by 360 degree times the magnetic field due to the complete loop, mu not i2 divided by 2 r2.
03:09
So plugging in the known values here for theta this is 120 degree divided by 360 degree, mu not 4 pi into 10 dash power minus 7 tesla meter per amp here again for current i2 this is 0 .80 ampere divided by 2 times of radius which is 0, which is 4 cm or 4 into 10 .m...