For coil a, the magnetic field $B_a$ is:
$B_a = \frac{\mu_0 i}{2R_a}$
For coil b, the radius is half that of coil a, so $R_b = \frac{1}{2}R_a$. The magnetic field $B_b$ is:
$B_b = \frac{\mu_0 i}{2R_b} = \frac{\mu_0 i}{2(\frac{1}{2}R_a)} = \frac{\mu_0
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