00:01
Ampiers law is typically used to find the magnetic field of a long straight wire, but it really works for any long straight conductor carrying a current, as long as the current just depends on the variable radially outward.
00:22
In other words, something with cylindrical symmetry.
00:26
And a reminder of what amper's law says.
00:30
It says that the magnetic field projected along a path integrated all the way around the path is equal to mu not times the enclosed current.
00:45
So here we're going to take a look at the magnetic field in a situation where we have a conductor of finite thickness and it is hollow inside, almost like a coaxial cable without the middle cable down it.
01:06
So just a tube.
01:09
And if we are inside the tube, so if we are in the gap with r less than b, what we know is the enclosed current is equal to zero.
01:23
And through the symmetry of the situation, we thus conclude that b is equal to zero.
01:33
And then when we get inside the conductor, so an empyrian loop is shown there in green.
01:45
What we have to take into account is the amount of current enclosed.
01:52
The left -hand side of ampiers law, you almost never have to integrate.
02:00
Sorry, we have the later picture showing, i will hide it.
02:05
But you almost never have to integrate that left -hand side because you assume that the magnetic field is constant along a circular loop.
02:15
So for the loop shown b times 2 pi, r is equal to mu not times i enclosed.
02:27
And in order to figure out the enclosed current, it's good to think about a current density j, which is the i divided by the cross -sectional area.
02:44
And in this case, we're assuming, yeah, we have a total of little i.
02:50
Let's just call it a little i.
02:54
And the cross -sectional area is the cross -sectional area of the blue conductor.
03:03
So it's the difference between the outer circle with radius a squared minus the area of the inner circle removing.
03:18
The gap, which has radius b.
03:23
But anyway, the ion closed is munaut times the current density times the area enclosed by the empyrian loop, which is the circle that's encircled by the green minus, again, subtract the gap, area and closed by the that you're finding the magnetic field on.
04:08
Okay, and putting this all together, it looks a little bit weird, but the magnetic field is equal to 1 over 2 pi times the radius of the empyrian loop.
04:25
Then we have mu not, and then this kind of weird -looking current density that takes into account just the cross -sectional area of the conductor, and then multiplied by the cross -sectional area of the conductor enclosed by that loop.
04:49
So that's an important distinction...