00:01
In this problem on the topic of magnetism, we are shown in the figure the current that is produced by a wire of resistivity 1 .62 times 10 to the minus 8 or meters.
00:11
The magnitude of the current versus time is shown in the next figure.
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The vertical axis in that figure is set by is, which is 10 ampiers, and the horizontal axis scale is set by ts, which is 50 milliseconds.
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The point p is at a radial distance 9 millimeters from the center of the wire, and we want to find the magnitude of the magnetic field b i at point p due to the actual current i in the wire firstly at 20 then 40 and then 60 milliseconds next we'll assume that the electric field driving the current is confined to the wire and we want to find the magnitude of the magnetic field b i d at point p which is due to the displacement current in the wire again at 20 40 and 60 milliseconds and then we want to find at 20 seconds the direction of b .i and bid.
01:03
Now from the figure, we can see that i is equal to 4 ampiers when the time t is 20 milliseconds.
01:18
And so from here, the magnetic field due to the actual current bi is mu -not -i over 2 pi -r, and using the information given, this is 0 .089 miltas.
01:41
Next, if we are given the time of 40 milliseconds, the current is 8 ampiers.
01:53
And so using the equation above, we get the magnetic field b .i to be 0 .18 milliseconds.
02:14
And then for part c, we have at 60 milliseconds the current i is equal to 10 amperes since the current is 10 ampiers when t is greater than 50 milliseconds which means that the displacement current or rather the magnetic field b i is equal to 0 .22 millie teslas now for part d the displacement current in terms of of the time derivative of the electric field id is equal to epsilon not a, d, d, t...