00:01
For this problem on the topic of magnetism, we are shown a current i in the figure that is produced in a wire that has a resistivity of 1 .62 times 10 to the minus 8 o meters.
00:11
The magnitude of the current first time is shown in figure b, and we want to determine the magnitude of the magnetic field b .i at the point p due to the current i in the wire, firstly at 20 milliseconds, then at 40 milliseconds, and then at 60 milliseconds.
00:28
Next, we want to assume that the electric field that is driving the current is confined to the wire, and we want to determine the magnetic field bid at point p due to the displacement current in the wire at 20, 40, and 60 milliseconds.
00:43
And lastly, at point p, at a time of 20 seconds, we want to know the direction of b .i and bid.
00:50
So figure 35 indicates that the current i is equal to 4 ampires when the time is equal to 20 milliseconds, which means the magnetic field b .i is equal to nu not i over 2 pi r.
01:16
Putting in these values, we get bi to be 0 .089 mille teslers.
01:30
Now for part b, we can see that when the current i is 8 ampiers, this is a time t of 40 milliseconds.
01:45
And so as above, we get the midfield b .i to be approximately 0 .18 milliseconds.
01:59
And for part c, similarly, when the current i is 10 ampiers, this corresponds to the time to all times greater than 50 milliseconds.
02:11
So we get the magnetic field, b .i, to be 0 .22 milliseconds...