This occurs when the angle of refraction is 90 degrees. Using Snell's Law, we have:
$n_1 \sin(\theta_c) = n_2 \sin(90^\circ)$
Solving for the critical angle $\theta_c$, we get:
$\theta_c = \sin^{-1}(\frac{n_2}{n_1})$
Now, we need to find the maximum angle of
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