Question

Figure P11.54 shows a BJT common emitter self-bias amplifier circuit with a PNP transistor. Assuming $V_{B E}=-0.7 \mathrm{~V}$ and $\beta=120$, (a) find the value for $R_1$ that makes $I_E=-1.2 \mathrm{~mA}$. (b) Find the value for $R_C$ that will make $V_C=-6 \mathrm{~V}$. (c) Determine the slope of the dc load line. (d) Where would we place a bypass capacitor in this circuit, and why? Figure P11.54 can't copy

   Figure P11.54 shows a BJT common emitter self-bias amplifier circuit with a PNP transistor. Assuming $V_{B E}=-0.7 \mathrm{~V}$ and $\beta=120$, (a) find the value for $R_1$ that makes $I_E=-1.2 \mathrm{~mA}$. (b) Find the value for $R_C$ that will make $V_C=-6 \mathrm{~V}$. (c) Determine the slope of the dc load line. (d) Where would we place a bypass capacitor in this circuit, and why?
Figure P11.54 can't copy

Essentials of Electrical and Computer Engineering

David V. Kerns, Jr.,… 1st Edition

Chapter 11, Problem 54

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Step 1

2 \, \text{mA} \), we first need to determine the emitter voltage $ V_E $. Since $ I_E = -1.2 \, \text{mA} $, we can use Ohm's law to find $ V_E $ if we know the emitter resistor $ R_E $. However, since $ R_E $ is not provided, we will assume it is Show more…

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Figure P11.54 shows a BJT common emitter self-bias amplifier circuit with a PNP transistor. Assuming $V_{B E}=-0.7 \mathrm{~V}$ and $\beta=120$, (a) find the value for $R_1$ that makes $I_E=-1.2 \mathrm{~mA}$. (b) Find the value for $R_C$ that will make $V_C=-6 \mathrm{~V}$. (c) Determine the slope of the dc load line. (d) Where would we place a bypass capacitor in this circuit, and why? Figure P11.54 can't copy

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