This is done by multiplying $A$ with its transpose. The given matrix $A$ is
$$A=\left[\begin{array}{ll}4 & 6 \\0 & 4\end{array}\right]$$
So, $A^T$ is
$$A^T=\left[\begin{array}{ll}4 & 0 \\6 & 4\end{array}\right]$$
Then, $A^TA$ is
$$A^TA=\left[\begin{array}{ll}4
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