Question
Find a singular value decomposition of $A.$$$A=\left[\begin{array}{rr}-3 & 0 \\0 & -4\end{array}\right]$$
Step 1
Here, $A^TA$ is the same as $A$ because $A$ is a diagonal matrix. So, the eigenvalues of $A$ are the squares of the singular values of $A$. The eigenvalues of $A$ are $(-3)^2=9$ and $(-4)^2=16$. Show more…
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