00:01
In this question we are given this circuit.
00:03
So there are four things, there are four parts in this question.
00:06
So first we need to find equivalent resistance, then we need to find potential difference across each resistor.
00:13
The indicated currents, i -1 to i -5, and the power deliver to each resistor.
00:19
So to do part a, you first need to recognize that the 6 -oam and the 9 -oam, they are parallel to each other.
00:31
Okay, so i'm just going to redraw the circuit.
00:57
Okay, 6 om, 10 volts, 6 ome, 2 .4 ome, 6 ome.
01:05
Okay, so the 1 over 6 plus 1 over 9 inverse, you calculate you get 3 .6 oms.
01:15
So this is 3 .6.
01:18
Then you notice that this can be simplified into, 6 oms, 6 oms, 6 oms, and 6 oms.
01:43
So from here we can actually find the total resistance now.
01:47
So the equivalent resistance is equal to 6 plus 6 plus the parallel part.
01:55
And then you calculate you get 15 oms.
01:58
So this is the answer for part a...