00:01
So we're given f prime of x equals x minus a squared x minus b squared such that a and b are not the same.
00:24
Well, we would get maxima and minima derivative when we set this equal to zero.
00:32
Wait a minute.
00:40
Yeah, when we set that equal to zero.
00:43
So they've already done the derivative for me, x equals a or x equals b.
00:53
Okay, second derivative.
01:10
Derivative of the first times the second, plus derivative of the second.
01:28
Whoops, no, that's right, times the first.
01:43
If x is a, then i'm getting zero.
01:48
If x is b, then i'm getting zero.
02:03
Which indicates that these are inflection points, and so there's no max or min.
02:19
And so we're done.
02:21
But i just want to check something.
02:24
Um, first of all, i noticed that i made a mistake.
02:31
There should be a two there.
02:33
But if i were to just model apply f prime of x out.
02:45
And i'm just checking something.
02:46
You can actually stop the video now if you want to.
02:49
But i'm checking something.
02:51
X minus a squared would be x squared minus 2ax plus a squared.
03:04
X minus b squared is going to be x squared minus 2bx plus b squared.
03:15
Okay, if i keep going, just multiplying these together, x squared minus two, where did i get that x squared from? that's not right...