00:01
For this exercise, we are going to solve the given polynomial equation.
00:08
Let's first begin by listing the, listing the possible rational roots.
00:14
We take the factors of the final constant and divide by the factors of the leading term coefficient, which is just the one.
00:29
So we're working with positive negative 1, 2, 4, and 8.
00:33
We can check descartes ' rule of signs.
00:38
The sign changes, so we have an idea of how many positive negative roots we have or zeros we have.
00:45
Here we've got one sign change, another, and a third.
00:51
So as far as positive roots are concerned, or positive zeros, we have three or one.
01:04
Let's look at the negative case.
01:06
We would have x to the 4th plus x cubed plus 2x squared plus 4x squared plus 4x minus 8 and we would only have this one single sign change so with regard to negative roots or zeros we would only have one so let's use that information and use synthetic division to try to find one, try to find an actual root.
01:47
Let's start with negative 1.
01:51
Let's see how negative 1 works out.
01:55
We've got 1, negative 1, 2, negative 4, negative 8.
02:05
We drop the 1, multiply, we add, we multiply, add, multiply, add, multiply, add, multiply, add, multiply, add, apply and get a zero.
02:22
So we did find zero.
02:27
So one of the zeros here, one of the roots, is x equals negative one.
02:36
Let me separate that.
02:37
It looks like it could be mistaken for a four.
02:41
So let's check.
02:42
Let's fix that.
02:44
X equals negative one.
02:46
That's better.
02:48
Okay, so we've got, oh, we've got the negative root...