00:01
So in this question, we are looking to solve x to the fourth minus x cubed plus 2x squared minus 4x minus 8 equals 0.
00:10
So we're going to start by thinking about our rational zero test.
00:15
And we're thinking about the candidates for possible rational zeros here.
00:21
My possible rational zeros can be found by looking at factors of the constant term, in this case negative 8, over factors.
00:31
Of the leading coefficient, in this case one.
00:36
What are my factors of negative 8? well, they are plus or minus 1, plus or minus 2, plus or minus 4, and plus or minus 8, over factors of 1, which are just plus or minus 1.
00:53
And so the division by plus or minus 1 doesn't change anything.
00:59
My candidates for possible rational zeros this time are plus or minus 1.
01:05
Plus or minus two, plus or minus four, and plus or minus eight.
01:10
Yes? and so let's start with one, and we'll use synthetic division to test these possible rational zeros.
01:20
So let's write down our coefficients.
01:23
They are 1, negative 1, 2, negative 4, and negative 8.
01:31
We'll test 1 to start.
01:34
Okay.
01:36
So testing 1, i'm hoping to get 0.
01:38
At the end, drop down the 1, multiply by 1, add, multiply by 1, add, multiply by 1, add, multiply by 1, add, i didn't get 0, and so that didn't work, x equals 1 is not going to be one of my zeros this time.
02:08
And so, so let's check negative 1.
02:12
Okay.
02:13
Now our multiplier is negative 1.
02:15
1 times negative 1, negative 1, add negative 2.
02:22
Multiply by negative 1, add, multiply by negative 1, add, multiply by negative 1.
02:33
And this time, i am in fact getting 0, yes? what does that tell me? it tells me that negative 1 is a 0 and that x plus 1 is a factor of this quartic polynomial...