Question
Find an equation in $x$ and $y$ for the line tangent to the curve.$x(t)=t^{2}, \quad y(t)=t+5$ at $t=2$
Step 1
The derivative of $x(t) = t^{2}$ with respect to $t$ is $dx/dt = 2t$. The derivative of $y(t) = t+5$ with respect to $t$ is $dy/dt = 1$. Show more…
Show all steps
Your feedback will help us improve your experience
Charles Machakwa and 50 other Calculus 2 / BC educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find an equation of the tangent line to the curve at the point corresponding to the given value of the parameter. x = t - t^-1 , y = 5 + t^2 , t = 1
Find an equation for the line tangent to the parametric curve at the given value of $t$. $$ x=2 t-1, y=3 t+5, t=-1 $$
Parametric Equations, Polar Coordinates, and Conic Sections
Parametric Equations
Find an equation for the line tangent to the parametric curve at the given value ot $t .$ $$ x=2 t-1, y=3 t+5, t=-1 $$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD