Find an equation of the tangent line to the curve at the point corresponding to the given value of the parameter. x = t - t^-1 , y = 5 + t^2 , t = 1
Added by Kelsey R.
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dy/dx = dy/dt / dx/dt dx/dt = 1 + t^-2 dy/dt = 2t dy/dx = (2t) / (1 + t^-2) Show more…
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