00:01
Hey guys, in this problem, we're going to be finding the equation to the line tangent of the function f of x equals e to the 2x at the point 0 .1.
00:09
So to do this, i'm going to, one, i'm going to graph the function and actually look at the line that intersects the point we're looking at here, 01.
00:21
And i am also going to be taking the derivative of our point to find the slope as well as solving for our constant here.
00:30
So to find the equation to the line tangent, we need to find an equation in this form, mx plus b.
00:39
And note that this form could look something slightly different.
00:43
It could look like this, or it could look like this.
00:53
It all depends on what equation you're looking at.
01:02
So let's go ahead and graph the function should look.
01:09
Something like this due to a little bit of experience with this kind of function.
01:17
So we know that at 0 .1, this function will intercept here, and it will behave something like this.
01:29
So this is our line that intercepts.
01:32
If i can draw it straight, please.
01:35
Let me redo that...