Question
Find an equation of the straight line tangent to the given curve at the point indicated.$$y=x^{3}+8 \text { at } x=-2$$
Step 1
We can do this by substitifying x = -2 into the given equation y = x^3 + 8. This gives us y = (-2)^3 + 8 = -8 + 8 = 0. So, the point is (-2, 0). Show more…
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