Question
Find the equation of the tangent line to the curve $y=\frac{8}{x^{2}+x+2}$ at $x=2$.
Step 1
We substitute $x=2$ into the equation $y=\frac{8}{x^{2}+x+2}$ to get $y=\frac{8}{2^{2}+2+2}=\frac{8}{8}=1$. So, the point is $(2,1)$. Show more…
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