00:03
All right, our first step is to find v of t, and that's the integral of a of t d t, which would be t squared over 2 plus c1, e to the t plus c2, and negative e to the negative t plus c3.
00:20
And if we use the vector v of zero equaling zero, zero, that would mean c1 equals zero, one plus c2 is equal to zero, which means c2 equals negative 1.
00:34
And negative 1 plus c3 equals 1, so c3 is equal to 2.
00:44
So v of t would be the vector t squared over 2, e to the t minus 1, and 2 minus e to the negative t.
01:00
And then r of t is the integral of v of t d t, which would be the vector t cubed over 6 plus a 1, e to the t minus t plus a2, 2t plus e to the negative t plus a3...