00:02
Okay, in this question, i'm looking for the first and second derivatives of a parametric curve at a given point.
00:11
I start with x equals 2 theta plus cosine theta and y equals 1 minus sine theta.
00:20
Be careful when you write these.
00:22
Be careful how you write these.
00:24
When i'm looking for d, y, d x, i need d -y -d - theta divided by d -e.
00:33
X d theta, but i always write down x first.
00:38
So i often end up with these upside down, so be really careful.
00:42
D .y d theta, and we're looking at theta equals pi over three.
00:47
So dy d theta is negative cosine of theta.
00:52
D x, d theta is two minus sine theta.
00:57
Now i want dy dx at theta is pi over three, so that's negative cosine pi over 3, which is negative 1.
01:11
Divided by 2 minus sine pi over 3.
01:16
That's 2 minus root 3 over 2.
01:20
You can simplify this as many times as you want to.
01:23
Multiplying the top and bottom by 2 might be my first choice.
01:27
Negative 1 over 4 minus root 3 is a little nicer...