00:01
Help us find the equation of a tangent line.
00:02
Recall the slope, sorry, the point slope form.
00:06
That's y minus the y value equals m x minus an x value.
00:11
We're already given the points.
00:12
We just need to find the respective slopes at those points.
00:16
So by implicit differentiation, we'll find the slope, plug in either point, and thus write the equation of the tangeline.
00:23
So the derivative of y squared is 2y, but times d, y, d, x.
00:28
The derivative of 5x squared is simply ten.
00:30
X, and if we isolate d -yd -x, we'll see that we get 5x over y...