00:01
All right, this problem wants us to find the sine of 2x, pen work, there it goes, find the sine of 2x, cosine of 2x and tangent of 2x from the given information.
00:24
And they're telling us the sine of x is equal to negative 3 5ths and that x is in quadrant three.
00:36
So what we need first is a really nice unit circle.
00:44
And i wanna make sure that i put my angle down here in quadrant three.
00:52
Now from right triangle trig, we should know soh cah toa.
00:58
And that of course stands for sine is opposite over hypotenuse.
01:03
So since theta is here, opposite is going to be negative 3, hypotenuse is gonna be 5.
01:10
And then we should recognize this as a 3 4 5 triangle.
01:14
So that's 4.
01:16
And from there we can find the cosine is adjacent over hypotenuse, so 4 over 5.
01:23
And our tangent is going to be opposite over adjacent, so negative 3 over 4.
01:31
And we need all of those things because now we have to find our double angles.
01:36
And i brought over the double angle identities already.
01:39
So when we are finding the sine of 2x, we just need to take two times the sine of x times the cosine of x.
01:50
Well, we know the sine of x is of course negative 3 5ths.
01:55
And we know the cosine of x is 4 5ths.
01:59
So this just becomes two times negative 3, which is negative 6 times 4, which is a negative 24 over 5 times 5, which is 25.
02:09
So the sine of 2x is negative 24 25ths...