00:01
In this exercise, we have to calculate both the wavelength and the frequency of a photon whose energy is 3 .1 electron volt.
00:11
So we know that the energy of a photon can be written as the constant, that planck's constant, h times frequency f.
00:21
And that frequency f can be written as c, the speed of light, over lambda.
00:29
So what we have to do is write e equals hc over lambda, which allows us to isolate lambda as hc over e.
00:45
Now we know that hc, hc equals 1 ,240 electron volts nanometers.
00:58
So we're going to have here, lambda equals 1240.
01:03
Electron volts nanometers over 3 .1 electron volts...