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Find the average value of the function on the given interval.

$ h(u) = \dfrac{(\ln u)}{u} $ , $ [1, 5] $

$\frac{(\ln 5)^{2}}{8}$

Calculus 2 / BC

Chapter 6

Applications of Integration

Section 5

Average Value of a Function

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Okay, let's use the average value Formula one over B, which is five minus a with just wants and the bounds of a which is one to be, which is five of our function. Natural overview over you, Do you? We know we could rewrite this as 1/4 from zero to natural log of five axe Deac. So what we're doing over here is we're transferring the function to the bounds to make it easier to plug in, because now we can do 14 times export over to this is the integral of acts from the bounds of zero to natural order five. So now we could have natural over five square dried by eight.

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