Question
Find the center and the radius of the circle $x^{2}+4 x+y^{2}-8 y=16$ (Hint: Express the given equation in the form$$(x-a)^{2}+(y-b)^{2}=r^{2}$$
Step 1
Step 1: Start with the given equation of the circle: \[ x^2 + 4x + y^2 - 8y = 16 \] Show more…
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