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Numerade Educator



Problem 38 Medium Difficulty

Find the critical numbers of the function.

$ g(x) = \sqrt[3]{4 - x^2} $


$x=0, \pm 2$

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Video Transcript

okay, We know that we can take the derivative the power of negative 2/3 times negative Two acts. Now let's consolidate everything negative. Two acts over three front sees four minus X squared to the 2/3. Now we know the derivative is equal to zero when x zero, Therefore, X zero is one critical number. And then we know the derivatives undefined when x is positive or negative to therefore to and negative to our other critical members.