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Find the critical numbers of the function.
$ g(x) = \sqrt[3]{4 - x^2} $
$x=0, \pm 2$
01:05
Wen Z.
Calculus 1 / AB
Calculus 2 / BC
Chapter 4
Applications of Differentiation
Section 1
Maximum and Minimum Values
Derivatives
Differentiation
Volume
Henry C.
October 13, 2021
why is 2 and -2 are
why is 2 and -2 are critical number
Missouri State University
Oregon State University
Harvey Mudd College
Idaho State University
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okay, We know that we can take the derivative the power of negative 2/3 times negative Two acts. Now let's consolidate everything negative. Two acts over three front sees four minus X squared to the 2/3. Now we know the derivative is equal to zero when x zero, Therefore, X zero is one critical number. And then we know the derivatives undefined when x is positive or negative to therefore to and negative to our other critical members.
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