We will use the product rule and the chain rule. The product rule is $(uv)' = u'v + uv'$ and the chain rule is $(f(g(x)))' = f'(g(x))g'(x)$.
The derivative of $x$ is $1$ and the derivative of $\sqrt{x-a}$ is $\frac{1}{2\sqrt{x-a}}$ by the chain rule. So, the
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