The magnitude of a vector is given by the formula $\sqrt{x^2 + y^2 + z^2}$, where x, y, and z are the components of the vector. In this case, the vector is $\langle 6,3,-2\rangle$, so the magnitude is $\sqrt{6^2 + 3^2 + (-2)^2} = \sqrt{36 + 9 + 4} = \sqrt{49} =
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