Question
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.)$ \langle 6, 3, -2 \rangle $
Step 1
The magnitude of a vector $\langle a, b, c \rangle$ is given by $\sqrt{a^2 + b^2 + c^2}$. So, the magnitude of the vector $\langle 6, 3, -2 \rangle$ is $\sqrt{6^2 + 3^2 + (-2)^2} = \sqrt{36 + 9 + 4} = \sqrt{49} = 7$. Show more…
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