For the first line, we can take $t=0$ to find a point $P(1,1,0)$ and the direction vector $\mathbf{v}_1=(1,6,2)$. Similarly, for the second line, we can take $s=0$ to find a point $Q(1,5,-2)$ and the direction vector $\mathbf{v}_2=(2,15,6)$.
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