00:05
And again, we're looking at domain and vertical and horizontal aspect.
00:10
So in the case of the function f of x equals x cube over x squared minus 1, we first want to find the domain restrictions, which means we want to find what makes that denominator equal to zero, because we know it can't equal zero.
00:24
So then there are two ways you can solve this.
00:26
You can solve it by square root, or you can solve it by factoring.
00:30
I'll do it by square root.
00:32
X squared equals one.
00:33
Take the square root of both sides.
00:35
We know x cannot equal positive or negative 1.
00:40
So our domain is going to be all real numbers not equal to positive or negative 1.
00:46
If you wanted to write that in interval notation, it would look like this.
00:50
Negative infinity to negative 1, parenthesis, union, or and also negative 1 to positive 1, and then 1 to infinity.
01:06
But that's kind of time consuming, and so i just generally will accept all real numbers except for whatever your excluded values are...