Question
Find the equation of all lines having slope 2 which are tangents to the curve $y=\frac{1}{x-3}, x \neq 3 .$
Step 1
$ The derivative of a function gives us the slope of the tangent line at any point on the curve. The derivative of $y=\frac{1}{x-3}$ is given by: \[y' = \frac{d}{dx} \left(\frac{1}{x-3}\right) = -\frac{1}{(x-3)^2}\] Show more…
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