00:01
In this question, we will be finding the equation of the line tangent to the curve defined by these parametric equations at the t -value pi over 6.
00:14
The topic of the problem is chain rule, so watch out for that during this video.
00:22
Okay, so to find the equation of the tangent line at a certain point, we need to know the x -coordinate and the y -coordinate of that point of tangency.
00:37
Where in this case t is equal to pi over six.
00:41
And we also need to know the slope of the tangent line at that point.
00:47
That is the derivative of y with respect to x at t equals pi over six.
01:00
Now since we're going to substitute t equals pi over six into these three different quantities, let's write the general forms of each of them in terms of t.
01:14
So for any value of t and then just substitute t equals pi over six for each.
01:33
We know that cosine of pi over six is root 3 over 2.
01:38
So secant, the reciprocal, is 2 over root 3.
01:44
Similarly, we know that sign is 1 half and cos is root 3 over 2.
01:51
And so the ratio, sine over cos, is 1 over root 3...