Question
Find the equation of the tangent line to the given curve at the given value of $t$ without eliminating the parameter. Make a sketch.$x=2 \sec t, y=2 \tan t ; t=-\frac{\pi}{6}$
Step 1
Given $y=2 \tan t$ and $x=2 \sec t$, we know that the derivative of $\tan t$ is $\sec^2 t$ and the derivative of $\sec t$ is $\sec t \tan t$. So, $\frac{dy}{dt} = 2 \sec^2 t$ and $\frac{dx}{dt} = 2 \sec t \tan t$. Show more…
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