00:01
And we once again need to go and find the equation to a line tangent to a function at a given point.
00:06
So we know that the line, and this time they give us the points as 1 -1.
00:11
So we know that y is equal to 1 and x is equals 1 in that point.
00:17
So they want us, so we know that y is equal to mx plus c is the equation for any straight line.
00:27
So we need to go find out what m and c will be in this case.
00:31
So m, once again, we know m is the derivative, or it's the gradient of a function, and in this case that will be the derivative of the function, the original function they gave us, at the point 1, x equal to 1.
00:51
And this, of course, will be the same as the limit as h approaches 0 of f in the point 1 plus h minus f in the point 1 over h...