Question
Find the equation of the normal to the curve $x^{3}+y^{3}=8 x y$ at the point where it meets the curve $y^{2}=4 x$ other than origin.
Step 1
By substituting $y^{2}=4 x$ into the first equation, we get $x^{3}+(2\sqrt{x})^{3}=8 x (2\sqrt{x})$. Solving this equation, we get $x=0$ and $x=4$. Show more…
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