💬 👋 We’re always here. Join our Discord to connect with other students 24/7, any time, night or day.Join Here! # Find the exact area of the surface obtained by rotating the curve about the x-axis.$y = \dfrac{x^3 }{6} + \dfrac{1 }{2x}$ , $\dfrac{1 }{2} \le x \le 1$

## Surface Area $$=\frac{263 \pi}{256}$$

#### Topics

Applications of Integration

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What I.

July 23, 2021

you are a terrible tutor

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Megan T.

October 14, 2021

your videos are super hard to follow when you skip important steps.

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### Video Transcript

this question asked us to find the exact area of the serfs obtained by routine the curve about the X axis. Have they stated we're looking at between 1/2 of one, So those are bounds and because we're rotating it, we know we need to add to pie. Not we know. Our original is X cubed over six plus one over to X. This is the original expression we've been given. We know this is also gonna be multiplied by why Prime squared. So one plus 1/4 ext the fourth, minus one house plus one over four ox the fourth and again, As I stated, this is the formula listed in the textbook where you've got, like, two pi when they've got why prime squared to two pi r squared or whatever the formula is how you consider it to be. We know now we take the integral. We do this by increasing the exponent by one and then dividing by the new exponents. You can also simple for the fractions as you go along. If that makes it easier for you to understand and remember our bouncer from 1/2 to 1 and this was given in the problem. Now that we have this, we know you need to plug end. So we're plugging in upper minus lower and you're probably gonna need a calculator for this. We end up with approximately 1.3 pie or 3.227 #### Topics

Applications of Integration

##### Top Calculus 2 / BC Educators ##### Catherine R.

Missouri State University ##### Heather Z.

Oregon State University  Lectures

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