In this case, the path starts at 2 meters, goes out to 10 meters, back to 8 meters, and then out to 10 meters again. So, the total distance traveled is $2 \, \text{m} \, \text{to} \, 10 \, \text{m} = 8 \, \text{m}$, $10 \, \text{m} \, \text{to} \, 8 \, \text{m} =
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