00:02
Let's take a look at the length of sides of a couple of triangles and see if we can learn anything about the triangles once we found the lengths of their sides.
00:11
So the first triangle, triangle pqr, with vertices at p of 3, negative 2, 3, q701, and r1.
00:25
So we're going to have to use the distance formula three times.
00:28
So let's first start with the length from p to q.
00:34
We subtract x coordinates and square them.
00:37
We subtract y coordinates and square them.
00:38
We subtract z coordinates and square them.
00:41
So we're going to have 7 minus 3, subtracting x coordinates from p to q squared, plus 0 minus negative 2 squared, plus 1 minus 3 squared.
00:59
So this is going to be the square root of 4 squared, plus 2.
01:03
Squared plus negative 2 squared.
01:08
This is going to be the square root of 16 plus 4 plus 4, which is the square root of 24.
01:20
24 is 4 times 6.
01:22
So i can write this as 2 times a square root of 6, bringing the factor of 4, separating it from the factor 6, and the square root of 4 is 2.
01:33
If i look at the length from q, to r, again, same thing, subtract x coordinates, subtract y coordinates, subtract z coordinates, square each of those differences, sum them, and then take the square root.
01:48
So from q to r, the x coordinates are 1 minus 7 squared, plus y coordinates 2 minus 0 squared, plus z coordinates, 1 minus 1 squared, one squared.
02:10
I'm getting a little ahead of myself.
02:15
So i get negative six squared plus two squared plus zero squared.
02:22
It's going to give me the square root of 36 plus four plus zero.
02:32
It's going to be the square root of 40.
02:34
40 is four times 10.
02:37
Four is a perfect square so i can simplify this radical by making it two times a square root of 10.
02:45
And last but not least, the distance from p to r.
02:51
Same thing, square the x coordinate, square the difference of the x coordinates, the y coordinates, and the z coordinates.
02:57
So from p to r, i have one minus three squared plus two minus negative two squared plus one minus three squared.
03:13
This is going to give me negative two squared plus four squared.
03:19
Plus negative 2 squared.
03:21
I did not give myself enough room to write that.
03:28
So this is going to give me 4 plus 16 plus 4, which is the square root of 24, which is 24 is still 4 times 6.
03:46
The root of 4 is 2.
03:47
So this is 2 times a square root of 6.
03:52
So one of the things that we can notice right away is that this is an isoslis triangle.
03:57
We can see that because pq and pr have the same length like today.
04:20
It might be a right triangle also.
04:24
To see if it's a right triangle, we want to see if it satisfies the requirement.
04:28
The pythagorean theorem says a squared plus b squared equals c squared.
04:33
The hypotenuse is always going to be the longest side.
04:41
The longest side here was the one that had the square root of 40.
04:44
So i'm going to check is a squared, which is i'll call pqa, so 2 times a square root of 6 squared, plus the other shorter side is pr 2 times a square root of 6 squared.
05:08
And i want to see if that's equal to 2 times a square root of 10 squared...