00:01
So here we're given information about a certain triangle.
00:02
We have a p with 2 comma negative 1, comma 0, a second point q, which is 4 .1, comma, 1, and r, which is 4, negative 5, comma 4.
00:17
So mainly we have to apply distance formulas three times here.
00:21
So the distance of pq would be the square root of 4 minus 2 squared plus 2 squared plus 1 squared, so it would be 4 minus 2 squared, which is just 4, plus 1 minus 1 squared, which would be 2 squared, so that would be 4 plus 1.
00:44
So the length of this side is equivalent to 3, and we're going to repeat this process for pr.
00:54
So for pr, it would be the square root of 4 plus 16, and plus 16.
01:06
And we find as a result that this is equivalent to six...